Question

A car drives off a cliff at 30 m/s. The car lands 100 meters
from the base of the cliff. How tall is the cliff?

Answer 1

Answer:

Height of the cliff, H = 54.66 m

Explanation:

Given that,

Speed of the car, u = 30 m/s

The car lands 100 m from the base of the cliff.

We need to find the height of the cliff.

First we will find the time time needed for the car to reach the bottom of the cliff. It can be calculated as :

$t=\dfrac{h}{v}\\\\t=\dfrac{100}{30}\\\\t=3.34\ s$

Let H is the height of the cliff. Using second equation of motion as follows

$H=v_yt+\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}\times 9.8\times (3.34)^2\\\\H=54.66\ m$

So, the cliff is 54.66 m tall.