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Explanation:
The value 12 is between the perfect squares 9 and 16
This means we can write the following inequality [tex]9 < 12 < 16[/tex]
From here we apply the square root to all three sides and simplify like so
[tex]9 < 12 < 16\\\\\sqrt{9} < \sqrt{12} < \sqrt{16}\\\\3 < \sqrt{12} < 4[/tex]
and we see that the square root of 12 is between 3 and 4.
Using a calculator would confirm this
[tex]\sqrt{12} \approx 3.464[/tex]
Answer:
Step-by-step explanation:
Find the numbers closest to 12 on either side that are perfect squares:
1, 4, 9, 16, 25
12 is in between the numbers 9 and 16. The square root of 9 is 3 and the square root of 16 is 4. Therefore, the square root of 12 is in between 3 and 4.