Question

An triangle has 3 angles.The second angle is 50 degrees less than 4 times the first angle .The third angle is 40 degrees less than the first.Find the three angles.

Answer 1

Answer:

x=45 , y=130 , z=5

Step-by-step explanation:

$\textrm{Let }x,y,z\textrm{ be the first, second, and thirdds angle, respectively.}\\Given \left \{ {{y+50=4x} \atop {z+40=x}} \right. \Leftrightarrow \left \{ {{y=4x-50} \atop {z=x-40}} \right.\\ \textrm{The sum of all three angle in an triangle is }180^{o}: x+y+z=180\\\Rightarrow x+(4x-50)+(x-40)=180\\\Leftrightarrow x=45\\ Thus, x=45^{o},y=4(45)-50=130^{o},z=45-40=5^{o}$

Answer 2

All the angles of the given triangle x, y, and z are equal to 45, 130, and 5.

What is the sum of the angle of a triangle?

The sum of all the angles of a triangle is equal to the supplementary angle.

let the angles of the triangle be x,y,z then x + y + z = 180°

It is given that triangle has 3 angles in which the second angle is 50 degrees less than 4 times the first angle. The third angle is 40 degrees less than the first.

let the angles of the triangle be x,y,z

y = 4x - 50

z = x - 40

The sum of all the angles of a triangle is 180°.

x + y + z = 180°

x + 4x - 50 + x - 40 = 180°

6x - 90 = 180°

x = 45

Since,  x = 45 then the second number y = 130 and the third number z = 5.

Therefore, all the angles of the given triangle x, y, and z are equal to 45, 130, and 5.

Learn more about the sum of the angle;

https://brainly.com/question/4410854