Respuesta :
The equation of a straight line in slope
(
m
)
and intercept
(
c
)
form is:
y
=
m
x
+
c
Rewriting our equation in this form
→
y
=
−
x
3
+
2
Hence the equation is a straight line with slope
−
1
3
and y-intercept
+
2
We are asked to graph the line by plotting points.
For simplicity, I will choose the points where
x
=
0
and where
y
=
0
(NB: Any two points on this line would do)
x
=
0
→
y
=
2
y
=
0
→
−
x
3
+
2
=
0
→
x
=
6
Hence the graph is a straight line through
(
0
,
2
)
and
(
6
,
0
)
as shown below:
graph{-x/3+2 [-2.446, 10.04, -2.695, 3.55]}
(
m
)
and intercept
(
c
)
form is:
y
=
m
x
+
c
Rewriting our equation in this form
→
y
=
−
x
3
+
2
Hence the equation is a straight line with slope
−
1
3
and y-intercept
+
2
We are asked to graph the line by plotting points.
For simplicity, I will choose the points where
x
=
0
and where
y
=
0
(NB: Any two points on this line would do)
x
=
0
→
y
=
2
y
=
0
→
−
x
3
+
2
=
0
→
x
=
6
Hence the graph is a straight line through
(
0
,
2
)
and
(
6
,
0
)
as shown below:
graph{-x/3+2 [-2.446, 10.04, -2.695, 3.55]}