Question

Review the graph.

On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. Point z 1 is (4, negative 3) and point z 2 is (negative 3, 2).

Suppose z3 = z1 – z2.Which quadrant contains z3?

quadrant I
quadrant II
quadrant III
quadrant IV

Answer 1

Answer:

D

Step-by-step explanation:

Answer 2

The position of z3 is (d) quadrant IV

The given parameters are:

$\mathbf{z_1 = (4,-3)}$

$\mathbf{z_2 = (-3,2)}$

The expression for z3 is given as:

$\mathbf{z_3 = z_1 -z_2}$

So, we have:

$\mathbf{z_3 = (4,-3) - (-3,2)}$

This gives

$\mathbf{z_3 = (4 + 3,-3 - 2)}$

$\mathbf{z_3 = (7,-5)}$

When the x-coordinate is positive, and the y-coordinate is negative, the point is in the fourth quadrant.

Hence, the position of z3 is (d) quadrant IV

Read more about quadrants at:

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