Respuesta :

Answer:

Step-by-step explanation:

86,101,116,131,146,...

a=86

c.d d=101-86=15

explicit formula

[tex]a_{n}=a+(n-1)d\\a_{n}=86+(n-1)15=86+15n-15=71+15n,n \in I,n>0\\[/tex]

recursive formula

[tex]a_{n}=a_{n-1}+15,a_{1}=86,n \in I,n \geq 2[/tex]

2.

112,110,108,106,104,...

a=112

c.d d=110-112=-2

explicit formula

[tex]a_{n}=112+(n-1)(-2) =112-2n+2=114-2n,n \in I,n>0[/tex]

recursive formula

[tex]a_{n}=a_{n-1}-2,a_{1}=112,n \in I,n \geq 2[/tex]

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