Answer: The last one/ D
Solve Absolute Value.
|4x+1|≤5
We know4x+1≤5and4x+1≥−5
4x+1≤5(Condition 1)
4x+1−1≤5−1(Subtract 1 from both sides)
4x≤4
4x4≤44(Divide both sides by 4)
x≤1
4x+1≥−5(Condition 2)
4x+1−1≥−5−1(Subtract 1 from both sides)
4x≥−6
4x4≥−64(Divide both sides by 4)
x≥−32
