Question

find the zeros of the function (x+3)^2(x-5)^6 and state the multiplicity

Answer 1

find the zeros of Function (x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6 = 0=> x--5= 0 => x = 5. Therefore real zero's of the function are --3,5.