A student pushes a television cart to the left with a constant force of 100 N. The force of friction between the cart and the floor pushes back to the right with a force of 75 N. If the cart was initially at rest, how will it move as the constant force is applied?

As you can see in the badly drawn picture below, the force pushing to the left is 100N while the opposing force pushing the right is 75N. These forces are subtracted from one another, which would leave us with a total force of 25N (100N - 75N = 25N) pushing to the left. Since the cart is initially at rest, this means that there is no additional force being applied left or right of the cart. Therefore, with the 25N of force, the cart would move at a constant speed to the left.

annyksl annyksl · Answer 2 · 2021-11-24T19:45:27+01:00

If the cart is at rest, it will move to the left at a constant speed.

We can arrive at this answer because:

The cart is at rest when no force is applied to it.

When the student pushes the cart to the left with a force of 100N, the cart will be forced out of rest if this force is greater than the drag force, which pushes the cart in the opposite direction.

As we can see, the force that pushes the cart in the opposite direction is equal to 75N, and therefore, we can say that the cart will move to the left.

However, the movement of the cart will not be done with a force of 100N, as 75N of this force will be canceled out, due to the force that pushes the cart in the opposite direction. In this case, the cart will move with a force of 25N.

More information:

https://brainly.com/question/18582537?referrer=searchResults