Question

What is the equation of a line through the points (0, 9) and (3, 0)?

Answer 1

(0,9) (3,0)

0-9 = -9
3-0= 3

slope = -3
y=mx+b

0=-3(3)+b
0=-9+b
b = 9

y=-3x+9

Answer 2

Answer:

Equation of line passing through two given points (0,9) and (3,0) is

y = -3x + 9

Step-by-step explanation:

Given : Two points of line as (0,9) and (3,0)

We have to find the equation of line passing through two given points .

The general form of an equation of line is given by y = mx + c where m is slope and c is y intercept.

Slope between two points is given by formula,

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(0,\:9\right),\:\left(x_2,\:y_2\right)=\left(3,\:0\right)$

$m=\frac{0-9}{3-0}=-3$

Put m = -3 in equation y = mx + c

we get , $y=\left(-3\right)x+c$

Put (0, 9) in above equation , x= 0 and y = 9

we have,

$9=\left(-3\right)\cdot \:0+c$

Simplify, we get, c = 9

Thus, equation of line passing through two given points (0,9) and (3,0) is y = -3x + 9