Answer:
a₆ = [tex]\frac{3}{8}[/tex]
Step-by-step explanation:
The n th term of a geometric progression is
[tex]a_{n}[/tex] = a₁ [tex]r^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 12 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{6}{12}[/tex] = [tex]\frac{1}{2}[/tex] , thus
a₆ = 12[tex](\frac{1}{2}) ^{5}[/tex] = 12 × [tex]\frac{1}{32}[/tex] = [tex]\frac{12}{32}[/tex] = [tex]\frac{3}{8}[/tex]
