Question

On a hot summers day, 613 people used the public swimming pool. The daily prices are 1.75 dollars for children and 2 dollars fir adults. The recipts for admission totaled 1127 dollars. How many children and how many adults swam at the public pool that day?

Answer 1

Answer:396  children and 217 adults swam at the pool.

Step-by-step explanation:

Step 1

let Children be represented as  x

and Adults  be represented as y

therefore

Step 2

x + y =  613.........equation 1 -----represents the 613 people (children and adults) that used the public swimming pool.

And

1.75x + 2.00y = 1127... equation 2------represents the daily prices which totaled 1127 dollars

Making x subject formulae in equation 1 and substituting in equation 2

x= 613-y

1.75(613-y) + 2.00y = 1127

1072.75 -1.75y+ 2y=1127

1127-1072.5 = -1.75y +2y

54.25=0.25y

y=54.25/0.25

y=217

Substitute y = 218 in (1)

x + 217= 613

x = 613-217

x = 396

396  children and 217 adults swam at the pool.

Answer 2

Answer: 396 children and 217 adults tickets were sold at the pool.

Step-by-step explanation:

Given data:

Number of people who used the pool = 613

Total sum on the receipt = 1127.

Price of adult tickets = $2

Price for children tickets = 1.75

Solution:

Let

Children = x

Adults = y

x + y = 613......... equation 1

1.75x + 2y = 1127..... equation 2

Multiply equation (1) by 2

2x + 2y = 1226........ equation 3

1.75x + 2y= 1127

Subtract (2) from (3)

0.25x = 99

x = 396

Substitute x = 396 in equation (1)

x + y = 613

396 + y = 613

y = 217

396 children and 217 adults tickets were sold at the pool.