Question

Find μsμsmu_s, the coefficient of static friction between the rod and the rails. Express the coefficient of static friction in terms of variables given in the introduction.

Answer 1

Answer:

The question is incomplete. However the complete question is :

A Rail Gun uses electromagnetic forces to accelerate a projectile to very high velocities. The basic mechanism of acceleration is relatively simple and can be illustrated in the following example. A metal rod of mass m and electrical resistance R rests on parallel horizontal rails (that have negligible electric resistance), which are a distance L apart. The rails are also connected to a voltage source V, so a current loop is formed.

The vertical magnetic field, initially zero, is slowly increased. When the field strength reaches the value $B_0$, the rod, which was initially at rest, begins to move. Assume that the rod has a slightly flattened bottom so that it slides instead of rolling. Use g for the magnitude of the acceleration due to gravity.

Find μs, the coefficient of static friction between the rod and the rails.

Express the coefficient of static friction in terms of variables given in the introduction.

So the answer is : $\mu_s=\frac{\Delta V LB_0}{Rmg}$

Explanation:

It is given : B = $B_0$

Therefore, using force on the current carrying wire is:

$\mu_s mg = B_0IL$

$\mu_s= \frac{ILB_0}{mg}$

Therefore,

$\mu_s=\frac{\Delta V LB_0}{Rmg}$

Answer 2

The coefficient of static friction in terms of variables will be $\rm \mu_s =\frac{ \triangle VLB_0}{Rmg}$.

What is the cofficient of static friction?

The ratio of the greatest static friction force (F) between the surfaces in contact before movement begins to the normal (N) force is the coefficient of static friction.

The given data in the problem is;

$\rm B=B_0$

The force on a current-carrying wire is balanced by the friction force.

The force on a current-carrying wire is given by;

$\rm \mu_s mg= B_0IL \\\\ \rm \mu_s=\frac{ILB_0}{mg}\\\\ \rm \mu_s= \frac{\triangle VLB_0}{Rmg}$

Hence the coefficient of static friction in terms of variables will be $\rm \mu_s =\frac{ \triangle VLB_0}{Rmg}$.

To learn more about the cofficient of static friction refer to;

https://brainly.com/question/17237604