Question

A vertical force is applied to a block of mass m that lies on a floor. What happens to the magnitude of the normal force on the block from the floor as magnitude F is increased from zero if force is (a) downward and (b) upward

Answer 1

Answer:

The answer is "$\bold{+9.0 \ \frac{m}{s^2}}$"

Explanation:

Its rate (in respect of time) was its derivative of its specified function x, as well as the speed is the derivative of the speed.  Therefore, in Newton's second legislation $a=2c- 3(2.0)(2.0)t$ is used:  

$F=(2.0 \ kg)a=40c -24t$ (understood by SI units).  

At $t=3.0s, the \ F=-36 \ N$ is told.  

Therefore, the solution of c can be used to solve $F=-36\ N=4.0c-24(3.0)$. This results in $c=+9.0 \ \frac{m}{s^2}$.