Answer: the coefficient of restitution of the ball for a collision with asphalt=0.95
Explanation:
Initial height of the bounce from the ball, h =2.47m
height of the 5th bounce of the ball , h₁= 1.51m
Making e the coefficient of the restitution, then the height covered by the ball after the 5th bounce is
h₁= e²ⁿh
Where n = 5
h₁= e²⁽⁵⁾h
e¹⁰=h₁/h
e¹⁰=1.51/2.47
e= (1.51/2.47)¹/¹⁰
e=0.95198≈ 0.95
Therefore, the coefficient of restitution of the ball for a collision with asphalt is 0.95
