Answer:
[Hg₂²⁺] = 1.3 × 10⁻¹⁶ M
Explanation:
Step 1: Given data
[Cl⁻]: 0.10 M
Solubility product constant of Hg₂Cl₂ at 25 °C (Ksp): 1.3 × 10⁻¹⁸
Step 2: Write the reaction for the solution of mercury (I) chloride
Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)
Step 3: Use the solubility product constant to calculate [Hg₂²⁺]
Ksp = 1.3 × 10⁻¹⁸ = [Hg₂²⁺].[Cl⁻]² = [Hg₂²⁺].(0.10)²
[Hg₂²⁺] = 1.3 × 10⁻¹⁶ M
