Answer: 1 student scored above an 85%.
Step-by-step explanation:
Let X = percentage score in test (normally distributed).
Given: Sample size = 15 , mean score : [tex]\mu[/tex]= 74.8% = 0.748 ,standard deviation : [tex]\sigma=7.57[/tex]
Now, The probability that student scores above 85%:
[tex]P(X>85)=P(\dfrac{X-\mu}{\sigma}>\dfrac{85-74.8}{7.57})\\\\=P(Z>1.347)\\\\=1-P(Z<1.347)\\\\=1-0.9110= 0.089[/tex]
Probability that student scores above 85% = 0.089
Number of students scored above an 85% = 0.089 x 15 = 1.335 ≈ 1
hence, 1 student scored above an 85%.