Answer:
[tex]\mathbf{P(X =11 ) \simeq 0.1429}[/tex]
Step-by-step explanation:
The objective of this question is to find the probability that:
Exactly 11 of them major in STEM
So, Let assume X to be the random variable that follows a binomial distribution:
Then [tex]X \simeq Bin ( 36, 0.31)[/tex]
The probability that exactly 11 of them major in STEM can be computed as:
[tex]P(X =11 ) = ^{36} C_{11} (0.31)^{11} (1-0.31) ^{36-11}[/tex]
[tex]P(X =11 ) = \dfrac{36!}{11!(36-11)!} \times (0.31)^{11} \times (0.69) ^{25}[/tex]
[tex]P(X =11 ) = \dfrac{36!}{11!(36-11)!} \times (0.31)^{11} \times (0.69) ^{25}[/tex]
[tex]P(X =11 ) =600805296 \times (0.31)^{11} \times (0.69) ^{25}[/tex]
[tex]\mathbf{P(X =11 ) \simeq 0.1429}[/tex]
Thus; the probability that exactly 11 of them major in STEM is 0.1429