Question

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes. They know that the probability of receiving a magazine subscription order with an entry form is 0.4. What is the probability that no more than a fourth of the entry forms will include an order

Answer 1

Answer:

The probability will be "0.0033".

Step-by-step explanation:

The given values are:

p = 0.4

1 - p = 1 - 04

       = 0.6

n = 16

By using the binomial probability formula, we get

⇒  $P(X = x) = ((\frac{n!}{x! (n - x)!} )\times px\times (1 - p)n - x$

⇒  $P(X \leq 1) = P(X = 0) + P(X = 1)$

⇒  $((\frac{16!}{0! (16)!} )\times 0.40\times (0.6)16 + ((\frac{16!}{1! (15)!} )\times 0.41\times (0.6)15$

⇒  $0.0033$ (probability)