Answer:
30.4g of Br2
Explanation:
2HBr --> H2 + Br2
From the stochiometry of the reaction;
2 mol of HBr reacts to form 1 mol of Br2
Mass of HBr = Molar mass * Mol = 80.91 * 2 = 161.82g
Mass of Br2 = Molar mass * Mol = 159.8 * 1 = 159.8g
161.82g of HBr forms 159.8g of Br2
30. 8g would the form x?
161.82 = 159.8
30.8 = x
x = 30.8 * 159.8 / 161.82 = 30.4g of Br2
