Answer:
0.93382
Step-by-step explanation:
Let
The event where a car has air conditioning (ac) be A
The event where a car has an automatic transmission be B
[tex]P(\text{Car has ac and cars that don't have automatic transmission})=P(A\cap B')=\dfrac{71}{136}[/tex]
[tex]P(\text{Car has car has an automatic transmission and no ac})=P(B\cap A')=\dfrac{56}{136}[/tex]
[tex]P(\text{Car has no ac and cars that don't have automatic transmission})=P(A'\cap B')=\dfrac{9}{136}[/tex]
The probability of a chosen car which has ac or automatic transmission or both
[tex]P(A\cup B)=1-P(A\cup B)'\\\Rightarrow P(A\cup B)=1-P(A'\cap B')\\\Rightarrow P(A\cup B)=1-\dfrac{9}{136}\\\Rightarrow P(A\cup B)=0.93382[/tex]
The probability that a randomly selected car had automatic transmission or air conditioning or both is 0.93382