Answer:
The average net force exerted on the car and riders by the magnets is 33751.8 newtons.
Explanation:
Let assume that car and its riders accelerate at constant rate, such that acceleration ([tex]a[/tex]), measured in meters per square second, can be found by using the following kinematic equation:
[tex]a = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 1)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the car and its riders, measured in meters per second.
[tex]t[/tex] - Acceleration time, measured in seconds.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 45\,\frac{m}{s}[/tex] and [tex]t = 6.8\,s[/tex], the average acceleration of the car is:
[tex]a = \frac{45\,\frac{m}{s}-0\,\frac{m}{s}}{6.8\,s}[/tex]
[tex]a = 6.618\,\frac{m}{s^{2}}[/tex]
By the Second Newton's Law, we find that average force exerted on the car and riders by the magnets ([tex]F[/tex]), measured in newtons, is:
[tex]F = m\cdot a[/tex] (Eq. 2)
Where [tex]m[/tex] is the mass of the car-riders system, measured in kilograms.
If we know that [tex]m = 5100\,kg[/tex] and [tex]a = 6.618\,\frac{m}{s^{2}}[/tex], the net force exerted on the car and riders is:
[tex]F = (5100\,kg)\cdot \left(6.618\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 33751.8\,N[/tex]
The average net force exerted on the car and riders by the magnets is 33751.8 newtons.