Question

Write a program that asks the user to enter a 10-character telephone number in the format XXX-XXX-XXXX. The application should display the telephone number with any alphabetic characters that appeared in the original translated to their numeric equivalent. For example, if the user enters 555-GET-FOOD, the application should display 555-438-3663.

Answer 1

In python:

number = input("Enter a 10-character phone number: ")

for i in number:

   if i.isalpha():

       if i == "A" or i == "B" or i == "C":

           i = "2"

       elif i == "D" or i == "E" or i == "F":

           i = "3"

       elif i == "G" or i == "H" or i == "I":

           i = "4"

       elif i == "J" or i == "K" or i == "L":

           i = "5"

       elif i == "M" or i == "N" or i == "O":

           i = "6"

       elif i == "P" or i == "Q" or i == "R" or i == "S":

           i = "7"

       elif i == "V" or i == "T" or i == "U":

           i = "8"

       elif i == "W" or i == "X" or i == "Y" or i == "Z":

           i = "9"

   print(i, end="")

I hope this helps!

Answer 2

Code:

def phonenumber():

alpha = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']

n =[2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9]

phone = input('Enter phone number in format of XXX-XXX-XXXX : ').upper()

index = 0

for index in range(len(phone)):

if phone[index].isalpha():

print (n[alpha.index(phone[index])], end = ' ')

else:

print (phone[index], end = ' ')

phonenumber()

Compilation output is attached below:

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