Question

A skateboarder rolls horizontally off the top of a staircase at a speed of
14.5 ms and lands at bottom of the stairs. The staircase has a horizontal length of
8.00m 8.00m8, point, 00, start text, m, end text. We can ignore air resistance. What is the skater's vertical displacement during the jump?

Answer 1

Answer:

The skater's vertical displacement during the jump is 1.49 meters

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed v from a height y, the range or maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle x=v\cdot\sqrt{\frac {2y}{g}}$

If we already know the value of x, we can solve the above equation for h:

$\displaystyle y=\frac {x^2g}{2v^2}$

We use the given values v=14.5 m/s, x=8 m, $g=9.8 m/s^2$:

$\displaystyle y=\frac {8^2\cdot 9.8}{2\cdot14.5^2}$

y = 1.49 m

The skater's vertical displacement during the jump is 1.49 meters

Answer 2

Answer:

The answer is -1.49 m not 1.49 m

Explanation:

It is referencing displacement from a higher point to a lower.