Question

A mixture of gases contains 8.00 g of He, 29.96 g of Ar, and 48.00 g of O2. What is the mole fraction of He in this mixture

Answer 1

Answer:

0.47

Explanation:

Mole = Mass / Molar mass

Helium;

Mole = 8 / 4 = 2

Argon;

Mole = 29.96 / 39.95 = 0.75

Oxygen;

Mole = 48 / 32 = 1.5

Total mole = 2 + 0.75 + 1.5 = 4.25

Mole fraction = Mole of He / Total mole

Mole Fraction = 2 / 4.25 = 0.47