Let the digit in one's place be y and digit at ten's place be x.
Given:
Sum of the digits = 11
⟶ x + y = 11
⟶ x = 11 - y -- equation (1).
And,
The number formed by reversing the digits is 27 more than the original number.
⟶ Reversed number = Original number + 27
reversed number = 10y + x.
⟶ 10y + x = 10x + y + 27
⟶ 10y + x - 10x - y = 27
⟶ 9y - 9x = 27
Substitute the value x from equation (1).
⟶ 9y - 9(11 - y) = 27
⟶ 9y - 99 + 9y = 27
⟶ 18y = 27 + 99
⟶ 18y = 126
⟶ y = 126/18
⟶ y = 7
Substitute the value of y in equation (1).
⟶ x = 11 - 7
⟶ x = 4
The number = 10(4) + 7 = 40 + 7 = 47.
∴ The required two digit number is 47.
I hope it will help you.
Regards.
