What is the original slope and what is the perpendicular slope?

Answer:
green line:
rise= -6
run= 3
rise/run = slope
therofore the slope = -6/3 = -2
blue line:
rise=3
run=6
rise/run = slope
therofore the slope = 3/6 = 1/2
Answer:
- 2 and [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 3, 5) and (x₂, y₂ ) = (0, - 1) ← 2 points on the green line
m = [tex]\frac{-1-5}{0+3}[/tex] = [tex]\frac{-6}{3}[/tex] = - 2
Repeat with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (6, 0) ← 2 points on the blue line
m = [tex]\frac{0+3}{6-0}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
Since the product of the slopes = - 2 × [tex]\frac{1}{2}[/tex] = - 1
Then the lines are perpendicular