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7. What is the distance between the points H(-5,9) and J(1,6)? Show your work.​

Respuesta :

6^2+-3^2= square root of the distance. The left side simplified is 36+9 or 45, then you take the square root of 45, so the distance is square root of 45 units.

Answer:

[tex] \huge{ \boxed{ \bold{ \sf{3 \sqrt{5} \: units}}}} [/tex]

Step-by-step explanation:

[tex] \sf{let \: H( - 5, \: 9) \longrightarrow \:(x1 \:, y1)}[/tex]

[tex] \sf{J(1 \:, 6) \longrightarrow \: (x2 \: ,y2)}[/tex]

[tex] \underline {\sf{ \: Finding \: the \: distance}} : [/tex]

[tex] \boxed{ \sf{distance = \sqrt{ {(x1 - x2)}^{2} + {(y2 - y1)}^{2} } }}[/tex]

[tex] \sf{⇢ \: distance = \sqrt{ {( - 5 - 1)}^{2} + {(9 - 6)}^{2} } }[/tex]

[tex] \sf{⇢ \: distance \: = \sqrt{ {( - 6)}^{2} + {(3)}^{2} } }[/tex]

[tex] \sf{⇢ \: distance \: = \sqrt{36 + 9}} [/tex]

[tex] \sf{⇢ \: distance \: = \sqrt{45} }[/tex]

[tex] \sf{⇢ \: distance = 3 \sqrt{5} \: units}[/tex]

Hope I helped !

Best regards! :D

~TheAnimeGirl

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