Given r(x)=x^3-4x^2+4x-6, find the value of r(2). What does your answer tell you about x-2 as a factor of r(x)? Explain.

Respuesta :

Answer:

-6

Step-by-step explanation:

r(2)=2^3-4(2)^2+4(2)-6

r(2)=8-16+8-6

r(2)=-6

The Value of r(2) is -6 and x-2 is not a factor of r(x).

What is the value of a function on a Variable?

A real-valued function of a real variable is a function that takes as input a real number, commonly represented by the variable x, for producing another real number, the value of the function, commonly denoted f(x).

What is Factor?

A factor of polynomial P(x) is any polynomial that divides evenly into P(x).

How to find out the value of r(x)?

Given  r(x)=x^3-4x^2+4x-6,

Put x = 2 ,

r(2)=2^3-4(2)^2+4(2)-6

r(2)=8-16+8-6

r(2)=-6

As we see that x=2 is not equal to zero,

implies x-2 does not divide r(x) evenly.

thus x-2 is not a factor of given r(x).

Learn more about factors on :

https://brainly.com/question/24380382

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