Answer:
239.2 N
Explanation:
Given that a vertical rope is attached to an object that has a mass of 40.0 kg and is at rest.The tension in the rope needed to give the object an upward speed of 3.50 m/s
in 0.700 s is
The tension in the rope and the weight of the mass will be acting in an opposite direction.
T - mg = ma ....... (1)
Where acceleration a = Velocity/ time
a = 3.5 / 0.7
a = 5 m/s^2
Substitutes acceleration a into the equation 1 above.
T - 40 × 9.8 = 40 × 5
T - 39.2 = 200
T = 200 + 39.2
T = 239.2N
Therefore, the tension in the rope needed to give the object an upward speed of 3.50 m/s
in 0.700 s is 239.2N
