Distance travelled in a velocity - time - graph is the area under the graph. The distance covered in the first 4 seconds of its motion is 4.8 meters
From the question and the given graph, the following parameters are given:
Total distance travelled S = 12m
The total time = 8 s
The velocity (V) of the car = ?
We can get V by using the area of a trapezium formula. That is,
S = 1/2( a + b )V
Where from the graph;
a = 2 and b = 8
Substitute a, b, and S into the above equation
12 = 1/2( 2 + 8 )V
24 = 10V
V = 24/10
V = 2.4 m/s
The shape of the distance covered in the first 4 seconds in the graph is triangle.
Area of a triangle = 1/2 x base x height
where
Area = distance covered
base = time = 4s
height = speed V = 2.4
The formula can be re-written as:
S = 1/2 x t x V
substitute all the necessary parameters into the above formula
S = 1/2 x 4 x 2.4
S = 4.8 m
Therefore, the distance covered in the first 4 seconds of its motion is 4.8 meters
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