Answer:
(6,1)
Step-by-step explanation:
In order to find the third point, you first need to identify the side length of XZ. X is (1, 1) and Z is (1, 5). In order to find the length of this segment, you just need to subtract 1 from 5 since that is the difference in the y-values and the x-values are the same.
Now, you know that XZ = 4. The problem says that the area of the triangle is 10, and the area of a triangle is a = [tex]\frac{1}{2}[/tex]bh, so you can just insert the values into the equation to solve for the base:
a = [tex]\frac{1}{2}[/tex]bh
= 10 = (1/2) * b * 4
= 10 = 2b
= 5 = b
Because the base is 5 units long, you can just add 5 to the x-value of the point Z, since Y is 5 units to the right of it
Y is (1 + 5, 1)
Y is (6,1)
