Question

A train left a station at 8:00 am going at 45 mph. A second train left the station at 10:00 am going in the same direction at 55 mph. At what time will the second train catch up with the first train?

Answer 1

Answer: At 5:00 pm the second train catch up with the first train.

Step-by-step explanation:

Let t = Time taken by first train.

Time taken by second train = t-2

Speed of train 1 = 45 mph

Speed of train 2 = 55 mph

Since, Distance = speed x time

Then, $45t= 55(t-2)$

$\Rightarrow\ 45t= 55t-110$

$\Rightarrow\ 55t-45t=110= \\\\\Rightarrow\ 10t=110\\\\\Rightarrow\ t=11$

After 11 hours, time = 8+11 =17(12+5)i.e. 5 : 00 pm.

Hence, At 5:00 pm the second train catch up with the first train.