Question

Please help, this has to do with kinematic equations

A body moving with uniform acceleration has a velocity of 15.9 cm/s when its x coordinate is 4.26 cm.
If its x coordinate 2.62 s later is −3.18 cm, what is the x-component of its acceleration?
Answer in units of cm/s²

Answer 1

Answer:

$a=-14.3\ cm/s^2$

Explanation:

Given that,

Initial velocity of a body, u = 15.9 m/s

Initial position, $x_i=4.26\ cm=0.0426\ m$

Final position, $x_f=-3.18\ cm=-0.0318\ m$

Time, t = 2.62 s

We need to find the x-component of its acceleration. using second equation of motion to find it as follows :

$x_f-x_i=ut+\dfrac{1}{2}at^2$

Putting all the values to find a.

$-3.18-4.26=15.9(2.62)+\dfrac{1}{2}a(2.62)^2\\\\-49.098=3.4322a\\\\a=-14.3\ cm/s^2$

So, the acceleration of a body is $-14.3\ cm/s^2$.