Question

Write an equation of the line passing through the point (8,-5) that is parallel to the line 2x – 6y=-3.
y = mx + b

Answer 1

Answer:

y=$\frac{1}{3}$x - $\frac{23}{3}$

Step-by-step explanation:

Ist put the first equation in y=mx+b form

2x-6y=-3

subtract 2x on both sides

2x-6y=-3

-2x    =-2x

-6y=-2x-3

then divide both sides by -6

-6y=-2x-3

-6

that gives y=$\frac{1}{3}$x+$\frac{1}{2}$ for the original equation

Then plug in the point and slope in y=mx+b

Use the same slope since the lines are parallel

(-5)=($\frac{1}{3}$)(8)+b

-5=$\frac{8}{3}$+b

then subtract 8/3 on both sides and that gives

-23/3 = b

then you can make the new equation using -23/3 for you b and 1/3 for your slop m