Answer:
[tex]P=1.95atm[/tex]
Explanation:
Hello!
In this case, since we are asked to compute the pressure of 0.175 moles of the given gas at 22.0 °C occupying a volume of 2175 mL, we can use the ideal gas equation as shown below:
[tex]PV=nRT[/tex]
Whereas our unknown is P and we solve for it as shown below:
[tex]P=\frac{nRT}{V}\\ \\P=\frac{0.175mol*0.082\frac{atm*L}{mol*K}*(22.0+273.15)K}{2175mL*\frac{1L}{1000mL} }\\ \\P=1.95atm[/tex]
Take into account that based on the given R units, the temperature must be in Kelvins and the volume in liters.
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