A gardener planted flowers of different colors.
of the flowers are yellow
The gardener planted 119 purple flowers. How many flowers did the
gardener plant?
of the remaining flowers are green.
• The rest of the flowers are purple. HELP FAST IM AWARDING BRAINLYEST

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Question:

A gardener planted flowers of different colors.

3/10 of the flowers are yellow.

3/4 of the remaining flowers are green.

The rest of the flowers are purple.

The gardener planted 119 purple flowers, how many flowers did the gardener plant?

Answer:

[tex]Total = 680[/tex]

Step-by-step explanation:

Represent Yellow with Y, Green with G and Purple with P

[tex]Y = \frac{3}{10}[/tex]

First, we need to determine the fraction of the rest.

[tex]Yellow + The\ Rest = 1[/tex] ---- In terms of fraction

[tex]The\ Rest = 1 - Yellow[/tex]

[tex]The\ Rest = 1 - \frac{3}{10}[/tex]

[tex]The\ Rest = \frac{10 - 3}{10}[/tex]

[tex]The\ Rest = \frac{7}{10}[/tex]

We have that:

[tex]G = \frac{3}{4} * The\ Rest[/tex]

[tex]G = \frac{3}{4} * \frac{7}{10}[/tex]

[tex]G = \frac{21}{40}[/tex]

To solve for the fraction of Purple, we make use of:

[tex]Y + G + P = 1[/tex]

[tex]P = 1 - Y - G[/tex]

Recall that: [tex]Y = \frac{3}{10}[/tex] and [tex]G = \frac{21}{40}[/tex]

So:

[tex]P = 1 - \frac{3}{10} - \frac{21}{40}[/tex]

[tex]P = \frac{40 - 12 - 21}{40}[/tex]

[tex]P = \frac{7}{40}[/tex]

At this point, we have the fraction of each flower as:

[tex]Y = \frac{3}{10}[/tex]

[tex]G = \frac{21}{40}[/tex]

[tex]P = \frac{7}{40}[/tex]

Also, we have that:

[tex]P = 119[/tex]

The relationship between both values of P is:

[tex]\frac{7}{40} * Total = 119[/tex]

[tex]Total = 119 * \frac{40}{7}[/tex]

[tex]Total = \frac{119 * 40}{7}[/tex]

[tex]Total = \frac{4760}{7}[/tex]

[tex]Total = 680[/tex]

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