Respuesta :
[tex] \sqrt{18 x^{9} y^{4} } = \\ = \sqrt{9*2 x^{8}*x* y^{4} }= \\ 3 x^{4} y^{2} \sqrt{2x} [/tex]
Answer: B ) 3x^4y^2sqrt 2x
Answer: B ) 3x^4y^2sqrt 2x
Answer:
Option B is correct
[tex]3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]
Step-by-step explanation:
Given the expression: [tex]\sqrt{18x^9y^4}[/tex]
Using exponent rule:
[tex]\sqrt[n]{x^n} = x[/tex]
we can write:
18 = [tex]3 \cdot 3 \cdot 2 = 3^2 \cdot 2[/tex]
[tex]x^9 = x^4\cdot x^4 \cdot x[/tex]
[tex]y^4 = (y^2)^2[/tex]
then;
[tex]\sqrt{18x^9y^4}[/tex] = [tex]\sqrt{3^2 \cdot 2 \cdot x^4 \cdot x^4 \cdot x \cdot (y^2)^2} = 3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]
Therefore, the following is equal to [tex]\sqrt{18x^9y^4}[/tex] is [tex]3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]