Respuesta :

[tex] \sqrt{18 x^{9} y^{4} } = \\ = \sqrt{9*2 x^{8}*x* y^{4} }= \\ 3 x^{4} y^{2} \sqrt{2x} [/tex]
Answer:  B ) 3x^4y^2sqrt 2x

Answer:

Option B is correct

[tex]3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]

Step-by-step explanation:

Given the expression: [tex]\sqrt{18x^9y^4}[/tex]

Using exponent rule:

[tex]\sqrt[n]{x^n} = x[/tex]


we can write:

18 = [tex]3 \cdot 3 \cdot 2 = 3^2 \cdot 2[/tex]

[tex]x^9 = x^4\cdot x^4 \cdot x[/tex]

[tex]y^4 = (y^2)^2[/tex]

then;

[tex]\sqrt{18x^9y^4}[/tex] = [tex]\sqrt{3^2 \cdot 2 \cdot x^4 \cdot x^4 \cdot x \cdot (y^2)^2} = 3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]

Therefore, the following is equal to [tex]\sqrt{18x^9y^4}[/tex] is [tex]3\cdot x^4 \cdot y^2 \sqrt{2x}[/tex]

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