Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equation. g(x)=-18(1/3)^x+2 Which statement correctly compares the two functions on the interval [-1, 2]? A. Only function f is increasing, but both functions are negative. B. Both functions are increasing, but function f increases at a faster average rate. C. Only function f is increasing, and only function f is negative. D. Both functions are increasing, but function g increases at a faster average rate.

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Answer: I think it's D.

Step-by-step explanation:

I'm on the same thing and my best answer is Both functions are increasing, but function g increases at a faster average rate.

Both functions are increasing, but function g increases at a faster average rate.

x         f(x)

-2        -46

-1         -22

0         -10

1           -4

2          -1

What is an increasing function?

If the slope of a function is continuously increasing or constant in an interval, the function is known as an increasing function.

Let us assume [tex]f(x)=ab^x+c[/tex]

at x=0, f(0)=-10

So, [tex]-10=a+c[/tex]

Similarly, by satisfying the above table in the f(x)

[tex]f(x)=-\frac{33}{5} (\frac{1}{11} )^x-\frac{17}{5}[/tex]

[tex]f'(x) > 0[/tex]

So we can say that f(x) is an increasing function.

[tex]g(x)=-18(\frac{1}{3} )^x+2[/tex]

[tex]g'(x)=-18(\frac{1}{3} )^xln(\frac{1}{3} )[/tex]

[tex]ln\frac{1}{3} < 0[/tex]

So, [tex]g'(x) > 0[/tex]

So, g(x) is an increasing function.

For any x∈f(x) and  x∈g(x) [tex]g'(x) > f'(x)[/tex]

So, g increases at a faster average rate

Thus,  Both functions are increasing, but function g increases at a faster average rate.

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