A ball is thrown straight downward with a speed of 0.50 meter per second from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released? [Neglect friction.]

Respuesta :

Answer:

The speed of the ball is 7.36 m/s

Explanation:

Constant Acceleration Motion

It happens when the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

[tex]v_f=v_o+at[/tex]

Since the situation corresponds to a vertical motion, the acceleration is g=9.8 m/s^2.

The ball is thrown downward at vo=0.5 m/s. Its speed at t=0.7 seconds is

[tex]v_f=0.5+9.8\cdot 0.7[/tex]

[tex]v_f=7.36\ m/s[/tex]

The speed of the ball is 7.36 m/s

Note: There is no use of the height it was released from

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