Question

find the temperature change of water when the mass is 45.0g and the intial temperature is 20.0C

Answer 1

Answer: The answer is 41.5 C

(45.0 g)(x - 20 C) = (22.3 g)(85 C - x )

45.0x + 900 C = 1895.5 C - 22.3x

+22.3 x - 900 C = -900 C + 22.3 x

67.3x = 2795.5

2795.5 / 67.3 = 41.54 C

Explanation: