Question

What is the energy of a photon with a frequency of 2.2 × 1016 Hz? Planck’s constant is 6.63 × 10–34 J•s.

Answer 1

First we need to find the wavelength from the frequency using $C = \lambda V$

so $3.0e8 = \lambda * 2.2e16 Hz$ which equals 1.36e-8 m then we use the formula $E =h \frac{C}{\lambda}$ we plug in $E = 6.63e-34 * (3.0e8/1.36e-8)$ and we get $E = 1.46e-17$

so the energy is 1.46 x 10^-17 J.

Answer 2

Answer:

A, 1.5 × 10 ^–17 J

Explanation:

edge