Respuesta :

Answer:

[tex]x = 1 \: or \: x = - 13[/tex]

Step-by-step explanation:

[tex]x^2+12x=13 \\ x^2+12x - 13=0 \\ x^2+13x - x - 13=0 \\ x(x + 13) - 1(x + 13) = 0 \\ (x - 1)(x + 13) = 0 \\ x = 1 \: or \: x = - 13[/tex]

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