Question

Which value of y forms the solution of the system defined by y = 11x + 1 and
11x + 12y = 12?

Answer 1

y = 11x + 1
  11x + 12y = 12
  Take the right side of the first equation, which is 11x + 1,
  (11x + 1) putting in second equation
 11x + 12y = 12
  Take out the y and put in (11x + 1) in place of the y
 11x + 12(11x + 1) = 12
using the distributive principle
11x + 132x + 12 = 12 Combine like terms on the left 143x + 12 = 12 Subtract 12 from both sides 143x = 0
 Divide both sides by 143 x = 0
 Now go back and get the very first equation
 y = 11x + 1
 And substitute (0) for x: y
= 11(0) + 1
  y = 0 + 1
  y = 1
hope rhis helps

Answer 2

y = 11 x + 1
11 x + 12 y = 12
----------------------
11 x + 12 * ( 11 x + 1 ) = 12
11 x + 132 x + 12 = 12
143 x + 12 - 12 = 12 - 12
143 x = 0
x = 0
y = 11 * 0 + 1
y = 0 + 1
Answer:
y = 1