Am I correct, if not please explain the correct answer.

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No buddy you are wrong .
Look ;
(( Left table )) :
[tex] \frac{y}{x} = 6 \\ [/tex]
[tex] \frac{48}{8} = 6 \\ [/tex]
[tex] \frac{60}{10} = 6 \\ [/tex]
[tex] \frac{72}{12} = 6 \\ [/tex]
Thus it is proportional .
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(( Right table )) :
[tex] \frac{y}{x} = \: .... \\ [/tex]
[tex] \frac{12}{6} = 2 \\ [/tex]
[tex] \frac{28}{7} = 4 \\ [/tex]
[tex] \frac{68}{8} = 8 \\ [/tex]
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Thus the left table is proportional and
y is 6 times x in it.
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