Question

Find a so that the point (-1,3) is on the graph of f(x) = ax^2 + 2

Answer 1

Answer:

a = 1

Step-by-step explanation:

Plug in the point into the equation, then solve for a:

f(x) = ax² + 2

3 = a(-1²) + 2

3 = a + 2

1 = a

So, a = 1

Answer 2

The points on a graph are the true values of the graph

The value of a is 1

The equation is given as:

$f(x) = ax^2 + 2$

At point (-1,3), the equation becomes

$3 = a(-1)^2 + 2$

Evaluate the exponent

$3 = a(1) + 2$

This gives

$3 = a + 2$

Subtract 2 from both sides

$a =1$

Hence, the value of a is 1

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