Answer:
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3 (s)[/tex]
Explanation:
Hello.
In this case, we can first write the complete molecular equation as shown below:
[tex]CaBr_2(aq)+Na_2CO_3\rightarrow CaCO_3 (s) +2NaBr(aq)[/tex]
In such a way, since all the species but calcium carbonate remain in aqueous solution, they are successfully dissociated whereas the solid product remain undissociated:
[tex]Ca^{2+}(aq)+2Br^-(aq)+2Na^+(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3 (s) +2Na^+(aq)+2Br^-(aq)[/tex]
Thus, we can cancel out bromide and sodium ions as spectator ions, in order to obtain the required net ionic equation:
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3 (s)[/tex]
Best regards!