Question

Given that the molar mass of the Red 40 dye is equal to 496.42 g/mol, how many grams of Red 40 food dye were in the 0.235 L solution of drink mix

Answer 1

Answer:

5.21 g

Explanation:

Density of Red 40 = molar mass/molar volume

since the molar volume = 22.4 L

Density of Red 40 = 496.42 g/mol/22.4 L

Density of 496.42 g/mol = 22.16 g/L

But;

density = mass/volume

volume of Red 40 = 0.235 L

mass = density * volume

mass = 22.16 g/L * 0.235 L

mass = 5.21 g

Answer 2

The mass of the red 40 dye in the 0.235 L solution is 5.21 g

• We'll begin by calculating the density of the red 40 dye. This can be obtained as follow:

Molar mass of red 40 dye = 496.42 g/mol

Molar volume = 22.4 L

Density =?

$Density = \frac{mass}{volume}\\\\ = \frac{496.42}{22.4}$

Density of red 40 dye = 22.16 g/L

• Finally, we shall determine the mass of the red 40 dye in the solution. This can be obtained as follow:

Density of red 40 dye = 22.16 g/L

Volume = 0.235 L

Mass of red 40 dye =?

Mass = Density × Volume

= 22.16 × 0.235

Mass of red 40 dye = 5.21 g

Therefore, the mass of the red 40 dye in the solution is 5.21 g

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