Answer:
hello your question is incomplete attached below is the complete question
Given you have a . 24 bit CPU The contents of memory are Address 412 413 Value0x120x34 Ox56 0x78 0x9A OxBC OxDEOxF1 0x23 414 419 418 420 415 416417 What is the value of the word in HEX beginning at address 414 if the machine is Little Endian? If it is Big Endian? Write your answer in HEX . Hex digits that are alphabetical should be written in uppercase For example A and not a Make sure that Ox appears at the beginning of your answer Do not put whitespace in your answer
Answer: Little Endian: 0x9A7856.
Big Endian: 0x56789A.
Explanation:
Given data :
24 bit CPU ( size of each word = 24 bit )
next we have to determine how many bytes are contained in each 24 bit word
= 24 / 8 = 3 bytes
with this information a word in Hex beginning at 414 will end at 416
when we use the Little Endian representation the last byte of the binary representation which is 416 will be stored first followed by 415 and then 414
hence the word beginning at 414 using little Endian = 0x9A7856.
For Big Endian the process is vice versa
Hence the word beginning at 414 using Big Endian = 0x56789A.
