Question

A force of 15 N applied to a spring compresses it by 4 cm. What is the potential energy of the spring in the compressed position

Answer 1

Answer:

f=kx ; potential energy of compressed spring is equal to W= f (average) * x ;

So,

f(average) = (0+f)/2 ;

Here, W= f*x/2 = 0.3 j

Explanation: